Upload files

Single file

References issue #774 and detail example code.

func main() {
    router := gin.Default()
    // Set a lower memory limit for multipart forms (default is 32 MiB)
    // router.MaxMultipartMemory = 8 << 20  // 8 MiB
    router.POST("/upload", func(c *gin.Context) {
        // single file
        file, _ := c.FormFile("file")
        log.Println(file.Filename)

        // Upload the file to specific dst.
        // c.SaveUploadedFile(file, dst)

        c.String(http.StatusOK, fmt.Sprintf("'%s' uploaded!", file.Filename))
    })
    router.Run(":8080")
}

How to curl:

curl -X POST http://localhost:8080/upload \
  -F "file=@/Users/appleboy/test.zip" \
  -H "Content-Type: multipart/form-data"

Multiple files

See the detail example code.

func main() {
    router := gin.Default()
    // Set a lower memory limit for multipart forms (default is 32 MiB)
    // router.MaxMultipartMemory = 8 << 20  // 8 MiB
    router.POST("/upload", func(c *gin.Context) {
        // Multipart form
        form, _ := c.MultipartForm()
        files := form.File["upload[]"]

        for _, file := range files {
            log.Println(file.Filename)

            // Upload the file to specific dst.
            // c.SaveUploadedFile(file, dst)
        }
        c.String(http.StatusOK, fmt.Sprintf("%d files uploaded!", len(files)))
    })
    router.Run(":8080")
}

How to curl:

curl -X POST http://localhost:8080/upload \
  -F "upload[]=@/Users/appleboy/test1.zip" \
  -F "upload[]=@/Users/appleboy/test2.zip" \
  -H "Content-Type: multipart/form-data"